Exam 5V0-22.23 topic 1 question 14 discussion

Answer D is correct vSAN ESA RAID-5 (2+1). Recommended minimum = 4 hosts (3 hosts + 1 spare)

Answer B :- 4 hosts vSAN OSA RAID-5 (3+1). Absolute minimum = 4 host (Absolute minimum: The least number of hosts to satisfy the policy)

The catch is Adaptive RAID-5/FTT-1 in the questions, so the answer is 3 hosts https://core.vmware.com/blog/adaptive-raid-5-erasure-coding-express-storage-architecture-vsan-8

D for vSAN8 ESA

D, minimum 3 hosts

Keyword is ESA, which require only 3

D. Requirements changed with vSAN 8. Now only need 3 hosts. https://core.vmware.com/blog/adaptive-raid-5-erasure-coding-express-storage-architecture-vsan-8#:~:text=RAID%2D5%20Using%20the%20vSAN%20Original%20Storage%20Architecture&text=Meaning%20that%20the%20data%20is,the%20availability%20of%20the%20data.

In ESA you need 3 hots

D https://core.vmware.com/resource/vsan-frequently-asked-questions-faq#section1

Ignore my previous answer. That is for OSA. Answer should be D . Min 3 host. https://core.vmware.com/blog/adaptive-raid-5-erasure-coding-express-storage-architecture-vsan-8 Option #2: FTT=1 using RAID-5 in a 2+1 scheme As shown in Figure 3, this writes the data in a VM as a stripe consisting of 2 data bits and 1 parity bit, across a minimum of 3 hosts. It consumes 1.5x the capacity of the primary data, delivering guaranteed space efficiency of resilient data across just 3 hosts

FOR R1 Mirror FTT=0, 3 nodes min FTT=1, 3 nodes min FTT=2, 5 nodes min FTT=3, 7 nodes min FOR R5/6 EC FTT=0, NA FTT=1, 4 nodes min FTT=2, 6 nodes min FTT=3, NA

RAID-5, 2+1, 3-5 hosts

D is the answer. vSAN ESA combines the space efficiency of RAID-5/6 erasure coding with the performance capabilities of RAID-1 mirroring. It introduces Adaptive RAID-5 erasure coding, ensuring guaranteed space savings, even in clusters with as few as three hosts.

https://www.yellow-bricks.com/2022/11/15/vsan-8-0-esa-introducing-adaptive-raid-5/