Fry 1: Full (deleted at the end of 14 restored point)
Sat 2: Incremental (deleted at the end of 14 restored point)
Sun 3: Full (Active full)
Mon 4: Incremental
Tue 5: Incremental
We 6: Incremental
Thu 7: Incremental
Fri 8: Incremental
Sat 9: Incremental
Sun 10: Full
Mon 11: Incremental
Tue 12: Incremental
We 13: Incremental
Thu 14: Incremental
Fri 15: Incremental
Sat 16: Incremental
So the answer is B 2 fulls and 2 incremental
3 Full and 14 Incremental:
BKP RP FCount ICount
Fr 1 F Deleted
Sa 2 I Deleted
Su 3 AF/I 14 3 14
Mo 4 I 13 13
Tu 5 I 12 12
We 6 I 11 11
Th 7 I 10 10
Fr 8 I 9 9
Sa 9 I/SF 8 8 (SF Deleted)
Su 10 AF/I 7 2 7
Mo 11 I 6 6
Tu 12 I 5 5
We 13 I 4 4
Th 14 I 3 3
Fr 15 I 2 2
Sa 16 I/SF 1 1 1
because the job starts on Friday and there will be a full taken on Sunday. so you have two backup chains from sunday to the next saturday and the first backups (friday and saturday) will be deleted because there are already 2 backup chains that make 14 restore points
A is correct:
1 F Is deleted
2 F Is keeped to keep the forward incremental chain intact before the next full chain meets 14 RP requierement
3 I Is keeped to keep the forward incremental chain intact before the next full chain meets 14 RP requierement
4 I Is keeped to keep the forward incremental chain intact before the next full chain meets 14 RP requierement
5 I
6 I
7 I
8 I
9 F
10 I
11 I
12 I
13 I
14 I
15 I
16 I
17 F
18 I
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