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Exam LSAT Section 1 Logical Reasoning All Questions

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Exam LSAT Section 1 Logical Reasoning topic 1 question 399 discussion

Actual exam question from Test Prep's LSAT Section 1 Logical Reasoning
Question #: 399
Topic #: 1
[All LSAT Section 1 Logical Reasoning Questions]

Bird-watchers explore a forest to see which of the following six kinds of birdsgrosbeak, harrier, jay, martin, shrike, wrenit contains. The findings are consistent with the following conditions:
If harriers are in the forest, then grosbeaks are not.
If jays, martins, or both are in the forest, then so are harriers
If wrens are in the forest, then so are grosbeaks
If jays are not in the forest, then shrikes are
If grosbeaks are in the forest, then which one of the following must be true?

  • A. Shrikes are in the forest.
  • B. Wrens are in the forest.
  • C. The forest contains both wrens and shrikes.
  • D. At most two kinds of birds are in the forest.
  • E. At least three kinds of birds are in the forest.
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Suggested Answer: A 🗳️
A straightforward chain. Choosing G mandates rejecting H (Rule 1). That in turn mandates rejecting J and M (Rule 2s contrapositive). And once J is gone, S must be chosen (Rule 4), which is A. W, the remaining entity, can be chosen but need not be, so neither B. nor C. must be true. And since the total number of birds here is 2 or 3, D. and E. are possible only.

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