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Exam SnowPro Core topic 1 question 177 discussion

Actual exam question from Snowflake's SnowPro Core
Question #: 177
Topic #: 1
[All SnowPro Core Questions]

Which Snowflake function will interpret an input string as a JSON document, and produce a VARIANT value?

  • A. parse_json()
  • B. json_extract_path_text()
  • C. object_construct()
  • D. flatten
Show Suggested Answer Hide Answer
Suggested Answer: A 🗳️
by tejarun at Nov. 25, 2022, 11:31 p.m.

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Chosen Answer:
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tejarun
Highly Voted 1 year, 11 months ago
Selected Answer: A
https://docs.snowflake.com/en/sql-reference/functions/parse_json.html
upvoted 7 times
...
Mallikharjuna452
Most Recent 4 months ago
parse_json()
upvoted 1 times
...
pranalig
5 months, 1 week ago
Correct Answer: A
upvoted 1 times
...
AnireddySaikiranReddy
8 months, 3 weeks ago
Correct Answer: B
upvoted 1 times
...
_yyukta
8 months, 4 weeks ago
Selected Answer: A
A parse_json()
upvoted 1 times
...
Marge23
1 year, 2 months ago
Selected Answer: A
correct
upvoted 1 times
...
singhks
1 year, 3 months ago
A is the answer. https://docs.snowflake.com/en/sql-reference/functions/parse_json
upvoted 1 times
...
examtopics_strata
1 year, 3 months ago
A is correct
upvoted 1 times
...
qaiserlatif
1 year, 8 months ago
Selected Answer: A
Interprets an input string as a JSON document, producing a VARIANT value. Syntax PARSE_JSON( <expr> )
upvoted 1 times
...
KarBiswa
1 year, 9 months ago
Selected Answer: A
parse_json
upvoted 1 times
...
ViniJsr
1 year, 10 months ago
The correct answer is A.
upvoted 1 times
...
SV1122
1 year, 10 months ago
Was on exam Dec 31st 2022
upvoted 2 times
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paknadeem
1 year, 11 months ago
Selected Answer: A
The correct answer is A
upvoted 3 times
...
KeshavaMugulur
1 year, 11 months ago
This should A for sure
upvoted 2 times
...

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A (35%)
C (25%)
B (20%)
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