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Exam PCAP topic 1 question 89 discussion

Actual exam question from Python Institute's PCAP
Question #: 89
Topic #: 1
[All PCAP Questions]

Which of the following expressions evaluate to True? (Choose two.)

  • A. str(1-1) in '123456789'[:2]
  • B. 'dcb' not in 'abcde'[::-1]
  • C. 'phd' in 'aplpha'
  • D. 'True' not in 'False'
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Suggested Answer: AD 🗳️

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Chosen Answer:
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aferiver
Highly Voted 1 year, 7 months ago
Selected Answer: AD
Correct text is: A. str(1-1) in '0123456789' B. 'dcb' not in 'abcde'[::-1] C. 'phd' in 'alpha' D. 'True' not in 'False' A. str(1-1) in ‘0123456789’ evaluates to True because str(1-1) is ‘0’ which is in ‘0123456789’. B. ‘dcb’ not in ‘abcde’[::-1] evaluates to False because ‘dcb’ is in the reversed string ‘edcba’. C. ‘phd’ in ‘alpha’ evaluates to False because there is no substring ‘phd’ in the string ‘alpha’. D. ‘True’ not in ‘False’ evaluates to True because the string ‘True’ is not a substring of the string ‘False’.
upvoted 8 times
swatiphadtare
1 year, 6 months ago
@aferiver - did you give exam recently? how many new questions?
upvoted 1 times
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Jnanada
Highly Voted 2 years, 3 months ago
Only D is correct
upvoted 7 times
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Damon54
Most Recent 9 months, 3 weeks ago
There is something wrong with the choices print (str(1-1) in '123456789'[:2]) print ('dcb' not in 'abcde'[::-1]) print ('phd' in 'aplpha') print ('True' not in 'False') False False False True
upvoted 2 times
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Damon54
9 months, 3 weeks ago
print (str(1-1) in '123456789'[:2]) False
upvoted 1 times
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zantrz
9 months, 4 weeks ago
Selected Answer: AD
str(1-1) in '0123456789'
upvoted 1 times
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stuartz
2 years, 5 months ago
Did the options change from: A. str(1-1) in '123456789'[:2] '0' in '12' is False B. 'dcb' not in 'abcde'[::-1] 'dcv not in 'edcba' is False C. 'phd' in 'aplpha' definitely False D. 'True' not in 'False' Only D is True
upvoted 3 times
stuartz
2 years, 5 months ago
edit: 'dcb' not in 'edcba' is False
upvoted 1 times
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carpmatias
2 years, 6 months ago
Selected Answer: BD
Definetely B and D: >>> 'dcb' not in 'abcde[1-::]' True >>> 'True' not in 'False' True
upvoted 2 times
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macxsz
2 years, 6 months ago
Selected Answer: D
As it is, only True is: D. 'True' not in 'False'
upvoted 2 times
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rocky48
2 years, 8 months ago
Selected Answer: BD
str(1-1) in [2:]"123456789" File "<stdin>", line 1 str(1-1) in [2:]"123456789" ^ SyntaxError: invalid syntax >>> 'dcb' not in 'abcde[1-::]' True >>> 'phd' in 'aplpha' False >>> 'True' not in 'False' True So its BD
upvoted 1 times
zantrz
9 months, 4 weeks ago
before providing any answer, please place the code into any IDE. In Pycharm: print("dcb" not in "abcde"[::-1]) returns False. To clarify, in the expression "dcb" not in "abcde"[::-1], the substring 'dcb' is indeed present in the reversed string 'edcba'. Therefore, the correct evaluation is False, not True.
upvoted 1 times
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Noarmy315
2 years, 11 months ago
AD is correct
upvoted 1 times
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mazimir
3 years, 1 month ago
Exception True False True
upvoted 4 times
techdawgs
2 years, 11 months ago
It also comes down to what is supposed to be the correct text. I have come across this question elsewhere with the below answers which would mean A & D were correct. A. str(1-1) in '0123456789' B. 'dcb' not in 'abcde'[::-1] C. 'phd' in 'alpha' D. 'True' not in 'False'
upvoted 5 times
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C (25%)
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