Exam PCAP topic 1 question 1 discussion

initially i value is 0, while condition fails as not equal to 0 So, it enters into else block and execute the increment statement. Now i become 1

i = 0 while i !=0: i = i -1 else: i= i+1 print(i) #output: 1

I just pass the e xam, be aware, 50% of same questions on exam, 25 are derivatives of existing ones, 25% new question

if there is an space between ! = it will fail

i = 0 print(f"initial-value: {i}") while i != 0: i = i - 1 print(f"while-value: {i}") else: i = i + 1 print(f"else-value: {i}") print(f"final-value: {i}") initial-value: 0 else-value: 1 final-value: 1

A is correct, condition for the WHILE loop is never satisfied hence the ELSE part is executed.

i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1 i=1

The answer should be A because i is 0 in the first line, which means While won't be execute, then direct goes in to else section. i = i +1 which means i = 0+1, the result is 1.

Answer is B

Answer is B

answer is A

The value of the i variable when the while loop finishes its execution will be 1. This is because the else clause of the while loop will be executed only if the condition of the loop (i != 0) is not met, which means that the loop will not be executed at all. Since the loop is not executed, the value of i will not be changed, and it will remain 0. However, the else clause will be executed, which contains the statement i = i + 1. This will set the value of i to 1, which is the final value of i when the loop finishes its execution.

To add to my previous comment the question is what is the variable after the while loop is run, it does not ask after the else?

is it possible that the answer is D, the variable becomes unavailable? Technically the else statement is: 0 = 0 + 1, we are saying nothing is equals to something? I know when we run the code and add a print statement the returned value is 1, but the code snipped does not include a print statement, so when the code is run without a print statement, we have to assume the answer is D noting is returned?

In [4]: i=0 In [5]: while i != 0: ...: i=i-1 ...: else: ...: i=i+1 ...: In [6]: i Out[6]: 1

i=0 so i becomes i+1 A is correct

A is right.