Exam PCAP topic 1 question 67 discussion

Answer is C, but with brackets inserted around (Ex1, Ex2) - or B uppercase Ex1

try: # TypeError: can only concatenate str (not "int") to str print( 'five' + 1 ) # ZeroDivisionError: division by zero print ( 5 / 0) except (TypeError, ZeroDivisionError): #correct #except TypeError, ZeroDivisionError: #SyntaxError: multiple exception types must be parenthesized #except TypeError ZeroDivisionError: #SyntaxError: invalid syntax #except TypeError + ZeroDivisionError: #TypeError: unsupported operand type(s) for +: 'type' and 'type' print('An error occured.') Output - An error ocurred Ans is B

B. except (Ex1, Ex2):

b. except (Ex1, Ex2):

B is corrrect answer

If you need to serve two different exceptions called Ex1 and Ex2 in one except branch, you can write: a. except Ex1 Ex2: b. except (Ex1, Ex2): c. except Ex1, Ex2: d. except Ex1 + Ex2:

# Answer is B. Point of Q is, you need to use () with except when more than 1. try: # TypeError: can only concatenate str (not "int") to str print( 'five' + 1 ) # ZeroDivisionError: division by zero print ( 5 / 0) except (TypeError, ZeroDivisionError): print('An error occured.')

Should be D

Answer should be A

The Answer is D: try: pass except TypeError+ZeroDivisionError: pass except: pass

B should be the answer, but aren't the Exception name case sensitive? In which case, B is not the answer.