If you ignore the fact the 1st is an invalid variable name and the spacing is all wonky, then the answer is D. It might be lst but its hard to know or sure because formating on this site is a nightmare for programming questions.
Anyway, if we ignore that, then we evaluate each item in the list [0,1,2,3,4] according to the lamba function x % 2 == 0, where x is each subsequent item in that list. If they evaluate to true, then that item is allowed to pass the filter into the new list (that is created by the list() function).
Remember that modulo % returns the remainder of the division (regardless of which way you go)
0 % 2 returns 0
1 % 2 returns 1
2 % 2 returns 0
3 % 2 returns 1
4 % 2 returns 0
only the items that evaluated to 0 will pass the filter.
Thats [0,2,4] with a length of 3
B.
you can not have a variable name where the initial character is a number '1st' it could be 'st1'.
The equal sign has a gap which is not recognised in python = =, it should have been ==
True. The assumption is that that should be an letter "l" given the choices. If the real exam had '1st' then B would be wrong since this code would not even compile.
The answer is #B. The code will cause a runtime exception.
The actual error is:
#TypeError: object of type 'filter' has no len()
we cant get the len of a filter object so we can not
print(len(list)
The only answer is B and noting else.
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