Exam PCEP-30-02 topic 2 question 88 discussion

1. `a` is assigned the value `1`. 2. `b` is assigned the value `0`. Next, we evaluate the expression `x = a or b`: - The `or` operator returns the first truthy value it encounters, or the last value if none are truthy. - `a` is `1`, which is truthy, so `x` will be `1`. Then, we evaluate the expression `y = not(a and b)`: - The `and` operator returns the first falsy value it encounters, or the last value if none are falsy. - `a` is `1` (truthy) and `b` is `0` (falsy), so `a and b` is `0`. - Applying the `not` operator to `0` (falsy) results in `True`, which is equivalent to `1` in Python. Finally, we compute `x + y`: - `x` is `1` and `y` is `1`. - So, `x + y` is `1 + 1`, which equals `2`. Therefore, the output of the code is: 2

b is the correct answer 1 or 0 and not(a and b)= = 1 and 1 = =2