1. Evaluate `y < z`:
7 < 3 => False
2. Evaluate `z > y`:
3 > 7 => False
3. Combine the first part with `and`:
False and False => False
4. Evaluate `y > z`:
7 > 3 => True
5. Evaluate `z < y`:
3 < 7 => True
6. Combine the second part with `and`:
True and True => True
7. Combine the results with `or`:
False or True => True
So, the value assigned to `x` is `True`.
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hovnival
1 month, 1 week agochristostz03
5 months, 2 weeks ago