Exam PCEP-30-02 topic 1 question 31 discussion

Let's analyze the code step by step: w = [7, 3, 23, 42] x = w[1:] y = w[1:] z = w y[0] = 10 z[1] = 20 print(w) w = [7, 3, 23, 42]: A list w is created with the values [7, 3, 23, 42]. x = w[1:]: This creates a new list x that is a slice of w, starting from index 1, i.e., x = [3, 23, 42]. Note that this is a shallow copy, meaning changes to x do not affect w. y = w[1:]: This creates another new list y which is also a slice of w, similar to x. So y = [3, 23, 42]. Like x, this is also a shallow copy. z = w: Here, z is assigned the reference to w, meaning any changes made to z will directly modify w. y[0] = 10: This modifies the first element of y, so y becomes [10, 23, 42]. However, since y is a separate copy, w remains unaffected by this change. z[1] = 20: This modifies the second element of z (and w, since z refers to w), so w becomes [7, 20, 23, 42]. Finally, when print(w) is called, it outputs: [7, 20, 23, 42] So the correct answer is B. [7, 20, 23, 42].

Answer is b: w = [7, 3, 23, 42] x = w[1:] y = w[1:] z = w y[0] = 10 z[1] = 20 print(w) # [7, 20, 23, 42]

b is correct answer