Exam PCEP-30-02 topic 1 question 10 discussion

Here's the breakdown of the code and its execution: Code Breakdown: d = {} Initializes an empty dictionary d. d[1] = 1 Adds a key-value pair to the dictionary: key 1 (an integer) with value 1. d['1'] = 2 Adds another key-value pair to the dictionary: key '1' (a string) with value 2. Note: 1 (integer) and '1' (string) are considered different keys in Python. d[1] += 1 Increments the value associated with the key 1 (integer) by 1. The value of d[1] becomes 2. Current State of d: The dictionary now contains: d = {1: 2, '1': 2} sum = 0 Initializes a variable sum to 0. for k in d: sum += d[k] Iterates through the dictionary's keys (1 and '1') and adds their corresponding values to sum: For k = 1, sum += d[1] → sum = 0 + 2 = 2 For k = '1', sum += d['1'] → sum = 2 + 2 = 4 Final Output: The value of sum is 4. Output: 4

Let's analyze this code step by step: d = {} creates an empty dictionary. d[1] = 1 adds a key-value pair where the key is the integer 1 and the value is 1. d['1'] = 2 adds another key-value pair where the key is the string '1' and the value is 2. d[1] += 1 increments the value associated with the key 1. So now d[1] becomes 2. sum = 0 initializes a variable sum to 0. The for loop for k in d: iterates over the keys in the dictionary. In each iteration, it adds the value associated with the current key to sum. After the loop, sum will contain: 2 (from d[1]) 2 (from d['1']) Therefore, the final value of sum will be 4. print(sum) will output this final value. So, the output of this code will be: 4

d = {} d[1] = 1 >> value of the key integer 1 is integer 1 d['1'] = 2 >> value of the key string '1' is 2 d[1] +=1 >> update the value of the key integer 1 to 1+1 =2 >>> final list is {1: 2, '1': 2} sum = 0 for k in d: sum += d[k] >> sum the values that associate to all the keys >> the answer is 2+2 = 4 (C) print(sum) print(d)

c is the correct answer

d = {} # Create an empty dictionary d d[1] = 1 # Add a key-value pair where key is 1 and value is 1 d['1'] = 2 # Add a key-value pair where key is the string '1' and value is 2 d[1] += 1 # Increment the value associated with the key 1 by 1 {1: 2, '1': 2} sum = 0 # Initialize sum to 0 for k in d: # Iterate over each key in the dictionary d sum = sum + d[k] # Add the value associated with key k to sum