Let's analyze the code snippet step by step:
nums = [1, 2, 3]
Creates a list nums with three elements: [1, 2, 3].
vals = nums
The variable vals is assigned the same reference as nums. Now both vals and nums point to the same list object in memory.
del vals[1:2]
The slice vals[1:2] selects the element at index 1 (value 2).
The del statement removes this element from the list. Since vals and nums point to the same list, the change affects both.
After this operation, the list becomes [1, 3].
Now evaluate the options:
A. nums is longer than vals
False. Both nums and vals refer to the same list, which now has a length of 2.
B. nums and vals are of the same length
True. Both nums and vals are the same list, so their lengths are equal.
C. vals is longer than nums
False. Both nums and vals refer to the same list.
D. nums and vals refer to the same list
True. nums and vals point to the same memory location, so they refer to the same list.
Correct Answers:
B. nums and vals are of the same length
D. nums and vals refer to the same list
vals = nums -> this statement means both the Vals & nums will share same memory pool
vals = noms[:] -> this means both have different memory pool
upvoted 2 times
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