The code performs the following steps:
1. `list1 = [1, 3]`: Initializes `list1` with the elements `[1, 3]`.
2. `list2 = list1`: Assigns `list2` to refer to the same list object as `list1`. Now both `list1` and `list2` refer to the same list in memory.
3. `list1[0] = 4`: Modifies the first element of `list1` to be `4`. Since `list2` refers to the same list, this modification is reflected in `list2` as well.
4. `print(list2)`: Prints `list2`.
Since `list2` refers to the same list as `list1`, after modifying `list1`, `list2` will also reflect the changes.
**Expected output:** `[4, 3]`
C is correct.
list1 and list2 point to the same location in memory.
upvoted 3 times
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