Exam PCAP-31-03 topic 1 question 7 discussion

Are you blind? s is lowercase, not uppercase, throughout the entire code snippet. Therefore, the output is 2. Try yourself: s = '2A' try: n = int(s) except ValueError: n = 2 except ArithmeticError: n = 1 except: n = 0 print(n)

Analysis Variable Name Case Sensitivity: The variable S is defined as '2A', but within the try block, s (lowercase) is used. Since Python is case-sensitive, s is not defined, and this will raise a NameError. Error Handling: The NameError is not explicitly caught by any of the except blocks (ValueError, ArithmeticError). Therefore, the generic except block will catch it. Output: Due to the NameError, the generic except block will execute, and n will be assigned the value 0. Given this information, the expected behavior of the code is: D. it outputs 0 This is because the NameError caused by the case mismatch between S and s will be caught by the generic except block, assigning n the value 0. Additionally, there is a minor formatting issue in the code snippet you provided, which should be corrected for the code to run properly. However, that doesn't change the output in this case.

I feel the output should be 0 so in my opinion the answer should be D

Answer C is correct. Print 2 #Explanation: S = '2A' try: n = int(S) except ValueError: n = 2 except ArithmeticError: n = 1 except: n =0 print(n)

C is the correct

Answer C is correct. It prints 2. Trying to parse "2A" to an int will result in an ValueError, which will then set n to 2 in its except branch. No further excepts or assignments to n are done afterwards and n is printed with its value 2.

Option "D = it outputs 0" is correct. Explanation: S = '2A' try: n = int(s) except ValueError: n = 2 except ArithmeticError: n = 1 except: n =0 print(n) Returns output 0.