Exam PCEP-30-02 topic 1 question 13 discussion

Since there is a slicing the str2 made a copy of str1.

let's analyze what's happening in the given code: str1 = 'Peter' assigns the string 'Peter' to the variable str1. str2 = str1[:] creates a slice of str1 that includes all characters (from beginning to end). This effectively creates a copy of the string. In Python, strings are immutable, which means when you create a copy of a string using slicing, it creates a new string object with the same content. Therefore, the correct answer is: A. str1 and str2 are different (but equal) strings. This is true because: str1 and str2 contain the same characters ('Peter') They are equal in terms of content However, they are separate string objects in memory Options B, C, and D are incorrect: B is wrong because they are not the same string object, but two different objects with the same content. C and D are incorrect because both strings have the same length.

A is correct. Slicing creates a copy of the string. Therefore, they are different strings, but if you compare them for equality you the result will be True as they have the same content.

B is the correct answer, because their memory addresses are same if you check in your IDE. hence B. str1 and str2 are different names of the same strings.

b is the correct answer

str1 = 'Peter' str2 = str1 print(id(str1), id(str2)) #same memory location : 123262391172144, 123262391172144 str2 = 'hell' print(str1, str2) print(id(str1), id(str2)) #on manipulation memory changes : 123262391172144, 123262391705072 hence, Str1 & Str2 are same Strings but different name.

B is the answer

The correct answer is A, since str2 get all the elements from str1, but it's a new variable, new string. If you change str1, str2 remains unchanged