Exam PCPP-32-101 topic 1 question 6 discussion

The use of a single asterisk (*) before the parameter name (arg) indicates that it can accept a variable number of unnamed positional arguments. When the function is called, these arguments will be collected into a tuple named arg. The **args parameter, with two asterisks (**), allows for a variable number of keyword arguments to be passed to the function. These arguments will be collected into a dictionary named args.

The code is correct. its important oto note that *followed by any name means a tuple of variable number of unnamed positional arguments, and **followed by any name means variable number of keyword arguments. this means code is correct. *args, **kwargs are just a convention.

Works fine, I tested it

B is not the Valid answer. But A is valid one. because *args or *arg in python hold possition argument as turple and not as list. So its false to say *args hold information as list.

AB are both correct

Just run it to verify that it's syntactically correct.

A is correct. B is wrong since *arg is a tuple, not a list C is wrong since *arg is the placeholder for unnamed arguments D is wrong since the parameter names can be changed code: def f1(*arg, **args): print(arg, type(arg)) print(args, type(args)) f1(1, 2, 3, a=1, b=2, c=3) output: (1, 2, 3) <class 'tuple'> {'a': 1, 'b': 2, 'c': 3} <class 'dict'>

B: *arg holds a tuple, not a list C & D: kwargs is a convention, can be changed. The important part is the asterisk(s)

What happens here is that **args is the same variable as *args. Therefore, the placeholder for positional arguments (unnamed arguments) is replaced by the named arguments. Correct answer is C