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Exam CAPM topic 1 question 45 discussion

Actual exam question from PMI's CAPM
Question #: 45
Topic #: 1
[All CAPM Questions]

The project manager has the following information about the estimated duration for an activity:
✑ Most likely [tM] `" 15 days
✑ Pessimistic [tP] `" 20 days
✑ Optimistic [tO] `" 10 days
What is the estimated duration of this activity, according to the triangular distribution technique?

  • A. 10 days
  • B. 15 days
  • C. 12.5 days
  • D. 5 days
Show Suggested Answer Hide Answer
Suggested Answer: B 🗳️
by nickname12 at Sept. 8, 2020, 1:47 a.m.

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sweety433
2 months, 1 week ago
TM+T0+TP/3 - 45/3 = 15 days
upvoted 1 times
sweety433
2 months, 1 week ago
TM+T0+TP/3 = 45/3 = 15 days
upvoted 1 times
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EmRH
1 year, 5 months ago
Why is the answer 15, not 12.5? I thought the triangulation technique is to add all three together, then divide by three.
upvoted 2 times
[Removed]
1 year, 4 months ago
If you add all three together and divide by three, the answer is 15. (10 + 15 + 20 = 45, 45/3 = 15).
upvoted 5 times
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ChymKuBoy
1 year, 6 months ago
Selected Answer: B
B for sure
upvoted 1 times
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UlrichIng
4 years, 1 month ago
Page 201 of 6th Edition of PMBOK Depending on the assumed distribution of values within the range of the three estimates, the expected duration, tE, can be calculated. One commonly used formula is triangular distribution: tE = (tO + tM + tP) / 3. So the answer is B. 15 Days
upvoted 4 times
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MoonManBlue
4 years, 2 months ago
Correct, should be 15
upvoted 3 times
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nickname12
4 years, 2 months ago
This should be 12.5 E = (O + P + ML)/3
upvoted 2 times
nickname12
4 years, 2 months ago
Sorry 15, not 12.5
upvoted 3 times
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