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Exam 1z0-819 topic 1 question 40 discussion

Actual exam question from Oracle's 1z0-819
Question #: 40
Topic #: 1
[All 1z0-819 Questions]

Given the code fragment:

What is the result?

  • A. The compilation fails due to an error in line 2.
  • B. 201
  • C. de
  • D. 203
  • E. The compilation fails due to an error in line 3.
  • F. The compilation fails due to an error in line 1.
Show Suggested Answer Hide Answer
Suggested Answer: E 🗳️
by Obalt at Feb. 7, 2023, 7:40 p.m.

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ASPushkin
5 months, 2 weeks ago
Selected Answer: B
if you don't notice the syntax error on line 3, то //is ok according to Implicit narrowing char d = 100 //returns "int" according to Numeric Promotion Rules (char) x + (char)y
upvoted 1 times
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[Removed]
8 months, 2 weeks ago
Selected Answer: B
Correct answer is B i did run it and it print 201
upvoted 1 times
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[Removed]
1 year, 5 months ago
E is correct. int = won't compile
upvoted 1 times
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Stavok
1 year, 7 months ago
Selected Answer: E
E is correct Tested
upvoted 1 times
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Jtic
1 year, 11 months ago
Selected Answer: E
char d = 100, e = 'e' ; // line 1 int x = d ; // line 2 int y = (int) e; // line 3 System.out.println ((char) x + (char) y) ;
upvoted 1 times
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RP384
1 year, 11 months ago
Selected Answer: E
"int =" will fail
upvoted 1 times
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Obalt
1 year, 11 months ago
There is a minor error on line 3. Should be int y = (int)e. Then B is correct answer
upvoted 1 times
KiraguJohn
1 year, 9 months ago
That minor error on line 3 is intentional otherwise an examiner would not expect you to know the ASCII code for all characters.
upvoted 2 times
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Obalt
1 year, 11 months ago
Correct answer is B
upvoted 1 times
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C (25%)
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