Exam 1z0-819 topic 1 question 5 discussion

E is correct

public class Foo { public static void main(String[] args) { for (var i = 0; i < 10; i++) { switch (i % 5) { case 2: i *= 2 * i; break; case 3: i++; break; case 1: case 4: i++; continue; default: break; } System.out.print(i + " "); i++; } } } // Result: // 0 8

E is correct! i = 0, 0%5 = 0, default get's hit. 0 get's printed and incremented to 1. i = 1, case 1 has no break so we increment i to 2 and continue. i=2, 2%5 = 2 so 2 * 2 *2= 8. we print 8 and increment to 9 i=9, 9%5 = 4. we increment i to 10 and continue. We exit the for loop as 10 is not smaller than 10.

i=0 -> 0%5 is 0 so we go to default and break, then print 0 and increment it, so the next iteration will have i = 2. I=2 -> 2%5 is 2 so we double I then break from the loop with I = 4 print 4, increment to 5 and continue. I=6 -> 6%5 is 1 so we just increment and continue (go to the next iteration) I=8 -> 8%5 is 3 so we just increment to 9 and break, print 9 then increment and reach 10 which is the end. So the answer is D.

E is correct

E is correct

E is correct i*= 2*i; -> i=2x2x2 -> 8

E is correct answer