Exam 1z0-808 topic 1 question 224 discussion

An erratum to my previous answer, the answer is B as a protected method can be accessed from another package ONLY if it is a subclass. Answer A is also correct but B is more complete, just in case it is better to always mark the "most correct answer".

Answer is B. To Test (attention to test in different packages and files, as stated): ---------------------------------------------------------------- package branch; import root.*; public class Plant extends Tree { public static void main(String[] args) { Plant t = new Plant(); t.m1(); // Answer A --- Ok, but incomplete. t.m1(); t.m3(); // Answer B --- Ok t.m1(); t.m3(); t.m4(); // Answer C --- Error t.m1(); t.m4(); // Answer D --- Error } } ------------------------- package root; public class Tree { public void m1() {} private void m2() {} protected void m3() {} void m4() {}; } ----------------------------------------------------------------

A/B are valid but if I have to choose one I will choose B

The correct answer is A, the methods "m2" and "m3" cannot be seen by the child class because even inheriting it is in a different package, the same occurs for "m4", because when visibility is not placed, it is put automatically the "default" visibility which is even more restricted than private, so it cannot be seen by the "Plant" class, the only method that can be instantiated is "m1", because it is the only one seen.