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Exam 1z0-808 topic 1 question 223 discussion

Actual exam question from Oracle's 1z0-808
Question #: 223
Topic #: 1
[All 1z0-808 Questions]

Given:

What is the result?

  • A. myStr: 7007, myNum: 7007
  • B. Error
  • C. myStr: 9009, myNum: 7007
  • D. myStr: 7007, myNum: 9009
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Suggested Answer: C 🗳️

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Chosen Answer:
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akbiyik
5 days ago
Selected Answer: C
The answer is C. The 'myStr' member variable of class App is different from the variable with the same name in the method doStuff.
upvoted 1 times
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iSnover
2 months ago
Selected Answer: C
The answer is the letter C, I tested it, if you want follow the code: public class Test { String myStr = "9009"; public void doStuff (String str) { int myNum =0; try { String myStr = str; myNum = Integer.parseInt(myStr); } catch (NumberFormatException ne) { System.err.println("Error"); } System.out.println("myStr: " + myStr + ", myNum: " + myNum); } public static void main (String[] args) { Test obj = new Test(); obj.doStuff("7007"); } }
upvoted 1 times
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C (25%)
B (20%)
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