Correct is B.
public class App {
public static void doSum(Integer x, Integer y) {
System.out.println("Integer sum is " + (x + y));
}
public static void doSum(double x, double y) {
System.out.println("double sum is " + (x + y));
}
public static void doSum(float x, float y) {
System.out.println("float sum is " + (x + y));
}
public static void main(String[] args) {
doSum(10, 20);
doSum(10.0, 20.0);
}
}
The answer is the letter B, a method overload occurs printing what is written in that answer.
upvoted 2 times
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