Correct. Answer is C.
In the first 'for', when trying to execute n.substring for the name "Peter", an exception will be thrown. So in the catch block it will print "Invalid Name", in the second 'for' it will print "omas" and the default values of the remaining elements of the pwd array.
It can be tested, iSnover give the source code below.
Correnct is C, there are no comments to make. If you want to test the code:
public class Main {
public static void main(String[] args) {
String names [] = {"Thomas", "Peter", "Joseph"};
String pwd [] = new String [3];
int idx = 0;
try {
for (String n: names) {
pwd [idx] = n.substring(2, 6);
idx++;
}
}
catch (Exception e) {
System.out.println ("Invalid Name");
}
for (String p: pwd) {
System.out.println (p);
}
}
}
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C. 
D. 
somrita90
3 months, 2 weeks agoyanoolthecool
1 week agoVicky_65
8 months, 2 weeks agocarloswork
1 year, 1 month agoiSnover
1 year, 2 months ago