Exam 1z0-808 topic 1 question 74 discussion

Correct answer is B, code for testing

Answer is c because there is space between nums 2= nums 1 that is not same as nums2

An online complier gave me B.

Answer is B , because array is a object

Assignment statement `nums2 = nums1`, where there's a space and both arrays will now point to the same memory location.

Answer : B and tested locally

or C if there is a typo error

Answer: B

Answer C public static void main(String[] args) { int nums1[] = {1, 2 ,3}; int nums2[] = {1, 2, 3 ,4 ,5}; nums 2 = nums 1; // not defined. The variable has a space between nums and 2 for (int i : nums2) { System.out.print(i + ":"); } }

Compilation fails: no variables "num 1" and "num 2" defined

Tested code provided by rachuk Even though both arrays have different sizes, there's no problem in reassigning their variables. Variables are still nothing else than references to objects.

correct one is B

B is correct

Correct answer is B, code for testing: public static void main(String[] args) { int nums1[] = {1, 2 ,3}; int nums2[] = {1, 2, 3 ,4 ,5}; nums2 = nums1; for (int i : nums2) { System.out.print(i + " : "); } }

Ran this program I was surprised with the result but A is correct

Compilation fails. It should be nums2 instead of nums 2.

B is corrent, in line 3 "nums2" becomes a reference of "nums1".