Exam 1z0-808 topic 1 question 23 discussion

d = (a<b)? ((a<c)?a :((b<c)?b : c)) : x a = 100, b = 102, c = 102, d = 100

x=103, a=100, b=102, c = 102

The d part can be brocken down as follows int d = (a<b)? (a<c)?a: (b<c)?b:c: x;

Answer - A

Answer is A. Here is the source code to test: public static void main(String[] args) { int x = 100; int a = x++; //x++ makes x=101 but returns old value so a =100 int b = ++x;// ++x makes x=102 and returns new value so b=102 int c = x++;//x++ makes x=103 but returns old value so c =102 int d = (a < b) ? (a < c) ? a:(b < c) ? b : c : x; //a<b=true-->(a<c)=true-->d=a System.out.println(d); }

A is the correct one. x = 103, a = 100, b = 102, c = 102, d = 100

a=x++ returns value before increasing => a=100

A is the correct

A is the correct answer

x=100 a=101 b=100 (a<b) false: return x; = 100

Answer is A. Here is the source code to test: public static void main(String[] args) { int x = 100; int a = x++; int b = ++x; int c = x++; int d = (a < b) ? (a < c) ? a:(b < c) ? b : c : x; System.out.println(d); }