Exam 1z0-809 topic 1 question 3 discussion

In java 8, count() acts as a terminal operation. so values will be printed. In java 9 or above, output might not be printed as the jre can determine the number from stream directly without using peek() operation on elements.

Answer is A

no output from java 9 and more

Answer is A. Each element is doubled and printed with peek operation, while result of count operation is ignored.

The correct answer is A.

In java 8 answer is A In java 9 or more answer is B

The answer is B, output might not be printed

A test.

Please help, i typed the code as following but i'm not getting any output, what can be wrong?: package birdie; import java.util.Arrays; import java.util.List; class Vehicle { public static void main(String[] args) { List<Integer> values = Arrays.asList (1, 2, 3); values.stream () .map(n -> n*2) //line n1 .peek(System.out::print) //line n2 .count(); } }

Yes the correct answer is 246, so A is the correct option.

Ans: A

The correct answer is B . when you use count() , you cant peak on the elements of the stream. The number of elements covered by the stream source, a List, isknown and the intermediate operation, peek, does not inject intoor remove elements from the stream (as may be the case for flatMap or filter operations). Thus the count is thesize of the List and there is no need to execute the pipelineand, as a side-effect, print out the list elements.