Exam 1z0-809 topic 1 question 136 discussion

Answer is A, tested Deque<Integer> nums = new ArrayDeque<>(); nums.add(1000); System.out.println(nums); nums.push(2000); System.out.println(nums); nums.add(3000); System.out.println(nums); nums.push(4000); System.out.println(nums); Integer i1 = nums.remove(); System.out.println(nums); Integer i2 = nums.pop(); System.out.println(nums); System.out.println(i1 + ":" + i2);

A is correct. Tested. Firstly 1000 is added (at the back), then 2000 is added to front, then 3000 is added to back and finally 4000 to front, so deque looks like 4000-2000-1000-3000 and remove and pop do the same thing which is take value from from of deque and those values are 4000 and 2000 which are printed.

A, tested

A,tested

B is correct