Exam 1z0-808 topic 1 question 132 discussion

Correct answer is: Compile error 1. List<String> arrList = new ArrayList<>(Arrays.asList(arr); the ) is absent. It must be (Arrays.asList(arr)) 2. System.out.println(s+ "removed"); // s cannot be resolved to a variable

Compile error because s scoop is only in predicate scoop

Answer is A. String [] arr = {"Hi", "How", "Are", "You"}; List<String> arrList = new ArrayList<>(Arrays.asList(arr)); if (arrList.removeIf( (String s) -> {return s.length() <= 2;})) { System.out.println(arrList); // [How, Are, You] System.out.println(s+ "removed"); // s cannot be resolved to a variable }

The answer is the letter A, in the third line of code there is no last ")" to close the Array's asList method.

Answer is A: import java.util.ArrayList; import java.util.Arrays; import java.util.List; public class Test { static int a1; public static void doProduct(Integer a){ a1 = a * a; } public static void doString(StringBuilder s) { s.append(" " + s); } public static void main(String[] args) { String [] arr = {"Hi", "How", "Are", "You"}; List<String> arrList = new ArrayList<>(Arrays.asList(arr)); if (arrList.removeIf((String s) -> {return s.length() <= 2;})) { System.out.println(s + "removed"); } } }

System.out.println(s +"removed"); s make compile error because s scoop only in predicate scoop

The correct answer is A variable "s" inside println statement is out of scope --> unreachable, causes Compile error Note: comment out println, code compiles and "Hi" is removed.

If you add the bracket (and the semicolon) and remove the System.out of "s" the code compiles fine. I 've tried to print the list and it works. The size change so you can remove elements

It used lambda function and a lambda function needs to have the bracket for the return part

Agreed

Correct, variable 's' in print statement is not visible. If there is no compilation error, then UnSupportedOperation Exception will be thrown as we cannot remove elements from Array backed List.