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Exam 1z0-819 topic 1 question 181 discussion

Actual exam question from Oracle's 1z0-819
Question #: 181
Topic #: 1
[All 1z0-819 Questions]

Given:



and the code fragment:



You want to examine the items list if it contains an item for which the variable count is below zero.

Which code fragment at line 1 will accomplish this?

  • A. if(items.stream().allMatch(i -> i.count < 0)) {
  • B. if(items.stream().anyMatch(i -> i.count < 0)) {
  • C. if(items.stream().filter(i -> i.count < 0).findAny()) {
  • D. if(items.stream().filter(i -> i.count < 0).findFirst()) {
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Suggested Answer: B 🗳️
by d7bb0b2 at Jan. 5, 2024, 12:21 a.m.

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ASPushkin
3 months ago
answer: D Optional<T> findAny() Optional<T> findFirst() boolean AllMatch​(Predicate<? super T> predicate) boolean anyMatch​(Predicate<? super T> predicate) answer: anyMatch​
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d7bb0b2
1 year ago
Selected Answer: B
B is correct: allmatch check for all element match with the condition and is shortcircuit. C and D retrive an object no a boolean value so if not compile.
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d7bb0b2
1 year ago
B is correct: allmatch check for all element match with the condition and is shortcircuit. C and D retrive an element no a boolean value so if not compile.
upvoted 1 times
...
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