Exam 1z0-808 topic 1 question 71 discussion

I agree, the correct answer B B

Answer is C, Math.Random can be<0.5

exception is caught in method, B.

THE ANSWER IS B

Tested. Answer is B. Source code: class MyException extends RuntimeException{} public class Test { public static void main(String[] args) { try { method1(); } catch (MyException e) { System.out.println("A"); } } public static void method1() { try { throw Math.random() > 0.5 ? new MyException() : new RuntimeException(); } catch (RuntimeException re) { System.out.println("B"); } } }

B is only correct answers, as MyException is subclass of RuntimeException, so it will be caught by the catch block in the method1.

B is correct beacause MyException extends Runtime exception.

B is Correct

It is B. Runtime catches MyException too.

Answer is B. Because MyException is RuntimeException.

correct answer is B because MyException is RuntimeException itself.

Answer is C!!!!!

correct answer is B class MyException extends RuntimeException{} public class Test{ public static void main(String[] args) { try { method1(); } catch (MyException e) { System.out.println("A"); } } public static void method1() { try { throw new MyException(); } catch (RuntimeException e) { System.out.println("bb"); } } }

E. compilation error at line n1 "Exception" needs to be declared

B , catch (RuntimeException re)” always catches a RuntimeException

the correct answer B