Exam CFPS topic 1 question 1 discussion

p.g. 17-14

To calculate the minimum vent size, we need to consider the flow rate of carbon dioxide and the strength of the enclosure. First, let's convert the enclosure strength from pounds per square foot (lb/ft²) to pounds per minute (lb/min) to match the flow rate of carbon dioxide. 9 lb/ft² * (156 lb/min) = 1404 lb/min Now, we compare the flow rate of carbon dioxide (156 lb/min) to the strength of the enclosure (1404 lb/min). The higher value, which is 1404 lb/min, represents the required vent size. Now, we convert this value to square inches: 1404 lb/min ÷ 30 in/min (since 1 lb/min equals about 30 in² of vent area) ≈ 47 in² So, the minimum vent size recommended for this application would be closest to option: C. 45 in² (290 cm²)

The Answer is B

The answer is B - 40 in2