The correct answer is C. “Bik”
Here is the explanation:
1. Client send "Blue" payload
2. Choice router matches the default route because we don't have a "Blue" case
3. Inside the default case we set the payload to "Red" and trigger the choice again with that payload
4. Now we have a "Red" case and inside we change the payload to "Blk" color.
"C" is correct. I just recreated the scenario on Studio . At first, it went to the "Default" part of the choice . Then, on the "auto call" , it entered to the "payload contains Red" choice and payload "Blk" was the final response .
C is correct - Payload is accessible to childflow (even if recursive), final choice sets payload to red which then sends it through top branch on second iteration.
But this contains listener as a source. I think it will throw error.
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