Exam AZ-104 topic 5 question 7 discussion

Correct Answer: C VNet1 10.11.0.0/16 = 10.11.0.1 - 10.11.255.255 (overlap VNet2) VNet2 10.11.0.0/17 = 10.11.0.1 - 10.11.127.254 (overlap VNet1) VNet3 10.10.0.0/22 = 10.10.0.1 - 10.10.3.254 (no overlap) VNet4 192.168.16.0/22 = 192.168.16.1 - 192.168.19.254 (no overlap) Possible peerings are: VNet1 -> Vnet3 VNet1 -> Vnet4 If a virtual network has address ranges that overlap with another virtual network or on-premises network, the two networks can't be connected.

Tested, in this context answer is correct. Vnet 2 and Vnet 1 can not be peered and also Vnet 2 and vnet3 or vnet 4 can not be peered. But tested more and discovered that Vnet1 can make a peering with Vnet 3 and Vnet4. Pay attention if there will be a modification in the answer. The strange way of Microshit qestions.

Considering IP overlapping, the correct answer is C

C is correct

But if VNet2 doesnt overlap with VNet3 or 4 why can't it be peered?

C is correct

C is right

This question was in exam 01/03/2024

there is no overlap between VNet2, VNet3

C: Vnet 3 and 4 Vnet 1 and 2 overlap

Correct Answer:C

Correct Answer:C

Correct Answer: C

Virtual Peering Requirements: • Virtual Peering comes in two forms: Virtual Peering for within a Region and Global Virtual Peering for across regions. The question does not limit the peering to one region. So peering permitted to VNET3 and VNET4 • Virtual Peering cannot have overlapping address spaces so no peering can be had with VNET2 until there is an address space change (requires recreation of the VNET). Therefore only logical answer is C: VNET3 & VNET4: Read Here: (https://docs.microsoft.com/en-us/azure/virtual-network/virtual-network-peering-overview)

Given answer is correct... Peering should NOT have overlapping Address Space/subnets

Possible peerings are: VNet1 -> Vnet3 VNet1 -> Vnet4

FYI: https://docs.microsoft.com/en-us/azure/virtual-network/virtual-network-manage-peering#requirements-and-constraints