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Exam 102-500 All Questions

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Exam 102-500 topic 1 question 96 discussion

Actual exam question from LPI's 102-500
Question #: 96
Topic #: 1
[All 102-500 Questions]

Which of the following are valid host addresses for the subnet 203.0.113.64/28? (Choose two.)

  • A. 203.0.113.64
  • B. 203.0.113.78
  • C. 203.0.113.65
  • D. 203.0.113.80
  • E. 203.0.113.81
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Suggested Answer: BC 🗳️

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CuriousLinuxCat
Highly Voted 1 year, 11 months ago
/28 is counting in 16. So it will range from .64 ~ .79 You need to use valid host addresses so the actual range is: .65 ~ .78 Why you ask? .64 is used to call the actual subnet. .79 is used for a Broadcast Address. Answer is B and C because .78 and .65 fall in the ranges mentioned above.
upvoted 9 times
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lucaverce
Highly Voted 1 year, 1 month ago
Selected Answer: BC
Network: 203.0.113.64/28 11001011.00000000.01110001.0100 0000 (Class C) Broadcast: 203.0.113.79 11001011.00000000.01110001.0100 1111 HostMin: 203.0.113.65 11001011.00000000.01110001.0100 0001 HostMax: 203.0.113.78 11001011.00000000.01110001.0100 1110 Hosts/Net: 14
upvoted 7 times
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Mchoeti
Most Recent 3 months, 1 week ago
Selected Answer: BC
only B and C please
upvoted 1 times
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iwkno6
1 year, 10 months ago
203.0.113.64/28 203.0.113.0100|0000 <-- 28 bits .64 is the network address so the range would be the remaining 15 (00001111), hence B & C are correct
upvoted 1 times
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phucpeta
2 years, 3 months ago
jump= 2^4=16=>16 ip/subnet => ip from .64 to .79 except .64 because it is ip subnet
upvoted 2 times
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salimzaza
2 years, 4 months ago
.65 .78
upvoted 1 times
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Audio00_02
2 years, 6 months ago
64+14=78 (sennò me scordo)
upvoted 2 times
Rini_Giannenzo
2 years, 6 months ago
sto ad albano un paesino prima di genzano
upvoted 1 times
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Community vote distribution
A (35%)
C (25%)
B (20%)
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