Exam LFCS topic 1 question 88 discussion

When the command line echo "foo bar" | tee bar | cat is executed, the following happens: echo "foo bar" prints "foo bar" to standard output (stdout). The | (pipe) symbol takes the output of the previous command and sends it as input to the next command. tee bar takes the input it receives from the pipe and writes it to standard output (stdout) as well as to a file named "bar". The second | (pipe) symbol takes the output of the previous command and sends it as input to the next command. cat takes the input it receives from the pipe and writes it to standard output (stdout). Therefore, the output that is created is: foo bar The output is printed to both the terminal (stdout) and the file "bar", but since the cat command only reads from standard input (stdin), it will only output "foo bar" to the terminal.

tricky question. Output is "foo bar". file created is bar. Answer is correct

Incorrect. Answer is D. output created bar. [student@centos ~]$ cat bar foo bar