Exam LFCS topic 1 question 121 discussion

$ echo '1 2 3 4 5 6' | while read a b c; do echo result: $c $b $a; done result: 3 4 5 6 2 1

Confirm in bash: a='1' b='2' c='3 4 5 6' So echo result: $c $b $a => result: 3 4 5 6 2 1

$ echo '1 2 3 4 5 6' | while read a b c; do > echo result: $c $b $a; > done result: 3 4 5 6 2 1

The given command sequence reads input numbers '1 2 3 4 5 6' and then uses a while loop to assign them to variables a, b, and c, respectively. It then echoes these variables in reverse order. Here's the output: makefile result: 3 2 1 So, the output will be "result: 3 2 1" for each iteration of the while loop, as it reverses the order of the input numbers.

The given command sequence reads a string "1 2 3 4 5 6" using the echo command, then pipes it to a while loop that reads each of the space-separated values into the variables a, b, and c in turn. The loop then echoes the values of c, b, and a in that order, preceded by the string "result: ". Since the loop reads the values into a, b, and c in that order, and the loop echoes them in reverse order, the resulting output will be: result: 3 2 1

a=1,b=2,c=3456 so echo 345621

the answer is correct, tested in lab. But i can't understand the logic of it... can anyone explain?