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Exam JN0-362 topic 1 question 14 discussion

Actual exam question from Juniper's JN0-362
Question #: 14
Topic #: 1
[All JN0-362 Questions]

In a stateless IPv6 auto-configuration scenario, what is the host's IPv6 address if the interface's MAC address is 12:34:ab:cd:ef:56?

  • A. fe80::1234:abff:fecd:ef56/64
  • B. fe8::1234:abff:fecd:ef56/64
  • C. fec0::1234:abff:fecd:ef56/64
  • D. fe80::1234:abcd:ef56/64
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Suggested Answer: A 🗳️

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nushadu
3 years, 6 months ago
ed@vMX_R1# run show interfaces terse em2 Interface Admin Link Proto Local Remote em2 up down [edit] ed@vMX_R1# run show interfaces em2 | match HARD Interface flags: Hardware-Down SNMP-Traps Current address: 0c:9e:24:d6:00:02, Hardware address: 0c:9e:24:d6:00:02 [edit] ed@vMX_R1# set interfaces em2.0 family inet6 [edit] ed@vMX_R1# commit commit complete [edit] ed@vMX_R1# run show interfaces terse em2 Interface Admin Link Proto Local Remote em2 up down em2.0 up down inet6 fe80::e9e:24ff:fed6:2/64 [edit] ed@vMX_R1#
upvoted 1 times
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kkched
3 years, 8 months ago
Using SLAC scenario for configuring 64 bit Interface ID part of IP address Subnet ID = 12:34:ab:fffe:fe:cd:ef:56 (inserting FFFE between first 24 bit Company ID and last 24 bit Manifacturer ID) then add subnet ID part of Link local scope wich is FE80::/10 We then find : fe80::1234:abff:fecd:ef56
upvoted 2 times
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LittleMing
3 years, 8 months ago
I think correct answer is A (the question is host's IPv6 EUI-64) Ref : https://blog.marquis.co/ipv6-and-junos-stateless-address-autoconfiguration-slaac/
upvoted 4 times
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FrankZane
3 years, 9 months ago
Not D?
upvoted 1 times
majorcompugeek
3 years, 5 months ago
No because D just appends the MAC address to fe80::<mac>/64. The right answer is derived using the follow EUI-64 conversion process: 1. Identify the 24 bit company ID and manufacture ID. MAC: 12-34-ab-cd-ef-56 Company ID (First 24 bits/First half of MAC): 12-34-ab Manufacture ID (Last 24 bits/Last half of MAC): cd-ef-56 2. Rewrite/Concatenate the new 64 bit address as follows <company id>-ff-fe-<manufacture id>: 12-34-ab-ff-fe-cd-ef-56 3. Drop the dashes and group into 4 byte groups separated by a colon (xxxx:xxxx:xxxx:xxxx). You should get 4 groups: 64 bit Address: 1234:abff:fecd:ef56 4. Now new address into the following to generate the new IPv6 SLAAC address: fe80::<new 64 bit address>/64 -> fe80::1234:abff:fecd:ef56/64
upvoted 3 times
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