Exam JN0-633 topic 1 question 136 discussion

Actual exam question from Juniper's JN0-633

Question #: 136
Topic #: 1

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useu@host# run show log debug
Feb 3 22:04:32 22:04:31.983991:CID-0:RT: ge-0/0/1.0:5.0.0.25/59028-
>25.0.0.25/23, tcp, flag 18
Feb 3 22:04:32 22:04:31.983997:CID-0:RT: find flow: table 0x582738c0, hash
53561(0xffff), sa 5.0.0.25, da 5.0.0.25, sp 59028, dp 23, proto 6, tok 20489
Feb 3 22:04:32 22:04:31.984004:CID-0:RT:Found: session id 0x14f98. sess tok
20489
Feb 3 22:04:32 22:04:31.984005:CID-0:RT: flow got session.
Feb 3 22:04:32 22:04:31.984006:CID-0:RT: flow session id 85912
Feb 3 22:04:32 22:04:31.984009:CID-0:RT: vector bits 0x2 vector 0x53a949e8
Feb 3 22:04:32 22:04:31.984012:CID-0:RT: tcp sec check.
Feb 3 22:04:32 22:04:31.984015:CID-0:RT:mbuf 0x4a82cd80, exit nh 0xa0010
Which two statements are true regarding the output shown in the exhibit? (Choose two.)

A. The outgoing interface is ge-0/0/1.0.
B. The packet is subject to fast-path packet processing.
C. The packet is part of the first-packet path processing.
D. TCP sequence checking is enabled.

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Suggested Answer: CD 🗳️

by miloskv at Oct. 4, 2020, 4:41 a.m.

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miloskv

4 years, 6 months ago

Why is this first path processing and not fast path? I think correct should be B and D. TCP Flag 18 should be Push/Ack, so TCP SYN is not there. I know that TCP SYN is not required for first path (new session) processing if TCP SYN check is disabled, but to me, nothing in the screenshot indicates that this is a first packet Please correct me if I am wrong and point me to the indicator that shows first path instead of fast path

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Exam JN0-633 topic 1 question 136 discussion

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miloskv

SY0-701