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Exam JN0-102 topic 3 question 117 discussion

Actual exam question from Juniper's JN0-102
Question #: 117
Topic #: 3
[All JN0-102 Questions]

-- Exhibit --
user@router> show route protocol static
inet.0: 12 destinations, 12 routes (12 active, 0 holddown, 0 hidden)
+ = Active Route, - = Last Active, * = Both
192.168.1.128/27 *[Static/5] 00:03:13
>to 10.20.106.10 via fe-0/0/5.1
192.168.1.144/29 *[Static/5] 00:03:13
>to 10.20.14.131 via ge-0/0/0.0
192.168.1.192/27 *[Static/5] 00:03:13
>to 10.18.1.1 via ge-0/0/1.0
192.168.1.128/28 *[Static/5] 00:01:06
>to 10.20.14.130 via ge-0/0/0.0
-- Exhibit --
Given the routing entries shown in the exhibit, which next-hop IP address will be used for the destination IP address 192.168.1.142? (Assume that only static routes are available for the destination.)

  • A. 10.20.106.10
  • B. 10.20.14.131
  • C. 10.18.1.1
  • D. 10.20.14.130
Show Suggested Answer Hide Answer
Suggested Answer: D 🗳️

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SCSS
4 years, 7 months ago
192.168.1.128/27 *[Static/5] 00:03:13 is a not correct because of the FastEthernet interface?
upvoted 1 times
kbk89
4 years, 4 months ago
D is correct, why you ask? because /28 is more specific than /27
upvoted 1 times
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