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Exam CTFL-2018 topic 1 question 31 discussion

Actual exam question from ISTQB's CTFL-2018
Question #: 31
Topic #: 1
[All CTFL-2018 Questions]

Tests have been specified for the latest software release and users have prioritised these.
However, there are some dependencies between tests as shown in the table below (e.g. Test ID. '123' cannot be run until Test ID. '456' has been successfully completed).

Which test execution schedule best meets the prioritisation and dependency conditions?

  • A. 3, 5, 7, 10, 2, 4, 6, 8, 9, 1.
  • B. 5, 7, 4, 3, 9, 10, 1, 6, 8, 2.
  • C. 6, 1, 2, 9, 4, 3, 5, 7, 8, 10.
  • D. 1, 4, 3, 5, 2, 7, 9, 10, 6, 8.
Show Suggested Answer Hide Answer
Suggested Answer: D 🗳️

Comments

Chosen Answer:
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MARIAPITA
1 month, 1 week ago
Option D is the closest to being correct. Although it has one mistake (Test 2 being run before Test 7), it respects most of the dependencies and prioritization better than the other options.
upvoted 1 times
MARIAPITA
1 month, 1 week ago
Modified Option D (correct version): Test 1 (no dependencies) Test 4 (depends on Test 1) Test 3 (depends on Test 4) Test 5 (no dependencies) Test 6 (depends on Test 5) Test 7 (no dependencies, but Test 2 depends on it) Test 2 (depends on Test 7) Test 9 (depends on Test 3) Test 10 (depends on Test 9) Test 8 (depends on Test 3)
upvoted 1 times
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Mleal
1 year, 9 months ago
It should be B because 5 is the first HIGH priority with no conditions.
upvoted 1 times
[Removed]
1 year, 7 months ago
D is correct, because if you run 5 first then you have to rrun 2 next because 7 is dependant on 2, that's why B cannot be correct, with D you get correct priority based on dependencies.
upvoted 4 times
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Community vote distribution
A (35%)
C (25%)
B (20%)
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