A. wrong T_INET_0 0x3 that means it passed 2 sla targets. If it missed then it
missed 1 SLA target which is the 3bit in the SLA_MAP binary 3rd bit 4(0 off) 2nd bit 2(1bit on) first 1(1bit on)
B. wrong T_INET_1 0x1 that means it passed 1 sla target. if it missed then it missed
2 2nd and 3rd bit in the sla_MAP
therefore what is left is C,D correct
B & C are correct:
B - 0x1 means that only one target is matched and no matter how many targets are configured, one target at least was missed, thus the claim "T_INET_1 missed one target" is correct
C - 0x0 also means that there are no targets configured
D - claim can't be proven by the output.
B & D
A. Wrong
B. When there are two SLA targets 0x1 means that only the first sla target was met and the second one missed. 0x2 would mean second target was met while first one was missed. 0x3 would mean both sla targets were met.
C. 0x0 means no targets were met ore there are no targets. Both ports have a latency over 20ms so this could be a sla target not met.
D. These seem to be in order by jitter. There are two sla targets and if this would be in order by best quality then T_INET_0 should be the first one since it meets both targets.
This is a tricky one! Unless someone has taken the exam and confirm the correct answers (100% correct), there is room for dicussion. We don't know how many SLA targets are configured, so the sla map is the problem.
If 2 targets are configured 0x1 means pass and fail, 0x2 fail and pass and 0x3 pass and pass. If its 3 targets its completly different. The same on Level3_DNS. 0x0 can also mean, that there is no SLA target configured - 7.2 Study_Gudie Page 316. So I would say B and D
C and D are correct. A is wring 0x3 means sla target 1 and SLA target are passed. B is wrong, 0x1 means sla target 1 is passed and target 2 and 3 are missed (if configured).
C is correct. 0x0 means either target SLA are not configured or all SLA targets are missed. D is correct as SLA targets are ordered by jitter.
A - obviously wrong
C - wrong, just run it in the lab and check it yourself. Health-check without a configured target will have sla_map=0xb
Easy to test, 0x0 means that every configured check failed, but you don't know just from this command output how many are configured.
if you open sdwan study guide page 227, the table has a star near 0x0 value with the explanation "also means that there are no sla configured" (I also double-checked in lab). if you think of the mechanic of the sla map, hex 0xb means 1011 in binary, which would translate in 3 passed sla and 1 missed.
D is not correct.This is not indicated by the provided output. The health-check does not explicitly show that members are ordered according to jitter. Instead, it displays state, packet loss, latency, jitter, MOS, and bandwidth statistics.
B& C are correct - 0x1 means that only on target is matched. T_INET_1 missed on target - Thus B is correct.
C I correct as there are in fact on targets defined for Level3_DNS as shown with sla (0x0). This is detailed in the SD-WAN 7.2 study guide on page 221.
Read page 221 in the study guide, so you can learn the sla target maps and what they mean.
0x0 - no mathed sla targets
0x1 - match target 1
0x2 - Match target 2
0x3 - Match both targets.
Thus C is correct, and D is wrong.
you mean 0x2 1 missed.
0x3 means 2 ok so there are 2 health-checks then B is Correct, D incorrect.
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