Refer to the exhibit. The exhibit shows the SD-WAN rule status and configuration. Based on the exhibit, which change in the measured latency will make T_MPLS_0 the new preferred member?
A.
When T_INET_0_0 has a latency of 250 ms.
B.
When T_MPLS_0 has a latency of 80 ms.
C.
When T_INET_0_0 and T_MPLS_0 have the same latency.
Page 204 in the 7.2 Study guide.
link-cost-threshhold(10) which means you need a 10% improvement over the highest selected member (T_INET_0_0). 101.349 / 1.10 (110%) = 92.135. That means that T_MPLS_0 would have to be lower than that value to be selected.
Answer B sets the latency to 80ms which is less than 92.135ms.
A: incorrect, this would make it last
B: correct, the adjusted value of T_INET_0_0 is 92.135 bringing it above a latency of 80
C: incorrect, if it was the same then it would use priority as its metric
D: incorrect because the adjusted value of 0_0 is still lower.
A. - wrong because INET_1_0 will still win MPLS_0
B. correct because 80ms will be better from the corrected metric of INET_0_0
C. Wrong because INET_0_0 has better priority
D. wrong because 100ms will be worst from the corrected metric of inter_0_0
13) The exhibit shows the SD-WAN rule status and configuration.
Based on the exhibit, which change in the measured latency will make T_MPLS_0 the new preferred member?
pag 203 guide 7.2
B. When T_MPLS_0 has a latency of 80 ms. Latenci en inet_0 is 101.349/1.10=92.14
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