Exam 201 topic 1 question 13 discussion

Based on the information provided in the image and the question, if a client with IP address 205.12.45.52 opens a connection to the virtual server, the member that will be used for the connection is: D. 172.16.20.4:80 This conclusion is drawn from the following observations: The load balancing method is set to "Least Connections" as shown in the VS_Web_Pool Settings table. The Web_Pool Member Statistic and Settings table shows the current status and connections for each member. Among the available members (B, D, and E), member D (172.16.20.4:80) has the least number of current connections at 22. Although member E has fewer connections (18), its priority is lower (1) compared to D's priority (3). Member B has more connections (42) than D, so it wouldn't be chosen under the least connections method. Therefore, given the least connections load balancing method and the current state of the pool members, the connection would be directed to member D (172.16.20.4:80).

Correct Answer is D - which is 172.16.20.4 Explanation: 5 the group fell, remained 4 - 3 - 1 there are 2 servers missing in the 4th group, the next one is activated, the 3rd group = number of servers < 2? No, they are equal, which means the 1st group will not be used Tested in the lab

To me its E. Priority group activation is less than 2. Looking at the priority groups it seems to me that Priority 5 - both down, so all of the other groups should be activated and be able to receive traffic ( all of them only consist of 1 pool member, which is less than 2). Moving on to the LB method - pool member E has least active connections.