Exam 312-49v10 topic 1 question 229 discussion

A is correct because Bytes to Gigabytes is 53

57,193,758,720 bytes bytes = 53.265838623 gigabytes https://www.unitconverters.net/data-storage/byte-to-gigabyte.htm

Capacity (in bytes) = Number of cylinders × Number of heads × Number of sectors per track × Bytes per sector Given the drive dimensions: Number of cylinders/disk = 22164 Number of heads/cylinder = 80 Number of sectors/track = 63 Bytes per sector (standard sector size) = 512 bytes Plug these values into the formula: Capacity = 22164 cylinders × 80 heads × 63 sectors/track × 512 bytes/sector Now, calculate the capacity: Capacity = 22164 × 80 × 63 × 512 = 57,193,758,720 bytes To express this capacity in more common units: 1 kilobyte (KB) = 1,024 bytes 1 megabyte (MB) = 1,024 KB 1 gigabyte (GB) = 1,024 MB So, the capacity of the described hard drive is approximately: 57,193,758,720 bytes ÷ 1,024 B/KB ÷ 1,024 KB/MB ÷ 1,024 MB/GB ≈ 53.26 GB

Using the formula: Capacity = (Number of cylinders) x (Number of heads) x (Number of sectors) x (Sector size) Converting the number of cylinders, heads, and sectors: 22,164 cylinders/disk = 2^32 - 1 cylinders 80 heads/cylinder = 2^7 heads 63 sectors/track = 2^6 - 1 sectors Therefore, the capacity of the hard drive is: (2^32 - 1) x (2^7) x (2^6 - 1) x 512 bytes/sector = 57.27 GB So the answer is (B) 57.19 GB.

The real answer is 57.19 GB