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Exam 312-49 All Questions

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Exam 312-49 topic 1 question 4 discussion

Actual exam question from ECCouncil's 312-49
Question #: 4
Topic #: 1
[All 312-49 Questions]

How many characters long is the fixed-length MD5 algorithm checksum of a critical system file?

  • A. 128
  • B. 64
  • C. 32
  • D. 16
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Suggested Answer: D 🗳️

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[Removed]
2 months, 4 weeks ago
Selected Answer: D
The correct answer is D. 16. The MD5 algorithm produces a 128-bit hash value, which is typically represented as a 32-character hexadecimal string, but in terms of raw bytes, it is 16 bytes long.
upvoted 2 times
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hoangviet88vn
2 years ago
C is correct
upvoted 1 times
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yogaditia15
2 years ago
32 characters
upvoted 1 times
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thebigdax
2 years, 5 months ago
Selected Answer: C
the digest is represented as hex so 2 char per byte, 128 / 8 = 16 * 2 = 32
upvoted 1 times
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zenguyaz
2 years, 11 months ago
The answer is correct, 32 characters. https://stackoverflow.com/questions/6317276/md5-is-128-bits-but-why-is-it-32-characters#
upvoted 2 times
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shpunk
2 years, 11 months ago
Selected Answer: D
16 characters
upvoted 1 times
Ariel235788
2 years, 11 months ago
Check zenguyaz source, its 16 bytes that part of your answer is correct but each byte is made up of 2 characters; hence 32 characters in length
upvoted 1 times
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ech
2 years, 11 months ago
Selected Answer: D
It doesn't matter whether we take a hash of system file or ordinary file. MD5 length is 128 bits. In chars it is 16 chars. 128/8 = 16. https://en.wikipedia.org/wiki/MD5
upvoted 1 times
Ariel235788
2 years, 11 months ago
You are correct on 16 byte length due to 128 bits. each byte is 2 characters though. 16 x 2 = 32 characters
upvoted 1 times
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Ariel235788
2 years, 11 months ago
But it does matter since its asking for the checksum. Not the fixed length output
upvoted 1 times
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