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Exam 312-49v10 All Questions

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Exam 312-49v10 topic 1 question 7 discussion

Actual exam question from ECCouncil's 312-49v10
Question #: 7
Topic #: 1
[All 312-49v10 Questions]

A honey pot deployed with the IP 172.16.1.108 was compromised by an attacker. Given below is an excerpt from a Snort binary capture of the attack. Decipher the activity carried out by the attacker by studying the log. Please note that you are required to infer only what is explicit in the excerpt.
(Note: The student is being tested on concepts learnt during passive OS fingerprinting, basic TCP/IP connection concepts and the ability to read packet signatures from a sniff dump.)
03/15-20:21:24.107053 211.185.125.124:3500 -> 172.16.1.108:111
TCP TTL:43 TOS:0x0 ID:29726 IpLen:20 DgmLen:52 DF
***A**** Seq: 0x9B6338C5 Ack: 0x5820ADD0 Win: 0x7D78 TcpLen: 32
TCP Options (3) => NOP NOP TS: 23678634 2878772 =+=+=+=+=+=+=+=+=+=+=+=+=+=
+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.452051 211.185.125.124:789 -> 172.16.1.103:111
UDP TTL:43 TOS:0x0 ID:29733 IpLen:20 DgmLen:84

Len: 64 -
01 0A 8A 0A 00 00 00 00 00 00 00 02 00 01 86 A0 . .............
00 00 00 02 00 00 00 03 00 00 00 00 00 00 00 00 ................
00 00 00 00 00 00 00 00 00 01 86 B8 00 00 00 01 . ..............
00 00 00 11 00 00 00 00 ........
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.730436 211.185.125.124:790 -> 172.16.1.103:32773
UDP TTL:43 TOS:0x0 ID:29781 IpLen:20 DgmLen:1104

Len: 1084 -
47 F7 9F 63 00 00 00 00 00 00 00 02 00 01 86 B8

  • A. The attacker has conducted a network sweep on port 111
  • B. The attacker has scanned and exploited the system using Buffer Overflow
  • C. The attacker has used a Trojan on port 32773
  • D. The attacker has installed a backdoor
Show Suggested Answer Hide Answer
Suggested Answer: A 🗳️

Comments

Chosen Answer:
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4bd3116
4 months, 1 week ago
Selected Answer: D
The large packet sent to port 32773 indicates a possible exploitation attempt or backdoor installation.
upvoted 1 times
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Malko59
1 year, 3 months ago
Selected Answer: A
I think A is correct. The attack starts with an initial network sweep on port 111. More information about this real case on: https://honeynet.onofri.org/scans/scan18/sol.html
upvoted 2 times
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bjornborg
1 year, 5 months ago
The NOP and the data string tells me buffer overflow, so B is my answer
upvoted 2 times
...
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