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Exam Certified Associate Developer for Apache Spark All Questions

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Exam Certified Associate Developer for Apache Spark topic 1 question 39 discussion

Which of the following code blocks applies the function assessPerformance() to each row of DataFrame storesDF?

  • A. [assessPerformance(row) for row in storesDF.take(3)]
  • B. [assessPerformance() for row in storesDF]
  • C. storesDF.collect().apply(lambda: assessPerformance)
  • D. [assessPerformance(row) for row in storesDF.collect()]
  • E. [assessPerformance(row) for row in storesDF]
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Suggested Answer: D 🗳️

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jds0
2 months, 3 weeks ago
Selected Answer: D
Option D is correct. See example code below: from pyspark.sql import SparkSession spark = SparkSession.builder.appName("MyApp").getOrCreate() data = [ (0, 43161, "A"), (1, 51200, "A"), (2, None, "B"), (3, 78367, "B"), (4, None, "C"), ] storesDF = spark.createDataFrame(data, ["storeID", "sqft", "division"]) def myFunction(row): return row[0] [myFunction(row) for row in storesDF.collect()]
upvoted 1 times
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ZSun
1 year, 4 months ago
There are many way to apply a function to dataframe. 1. apply, as shown in option D. but it should be apply(assessPerformance) 2. list comprehension: for row in df.collect() 3. foreach 4. map, but for RDD majorly
upvoted 1 times
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4be8126
1 year, 5 months ago
Selected Answer: D
The correct answer is D. Explanation: Option A uses the take() method to extract three rows from the DataFrame, but it applies the assessPerformance() function to each row outside of the DataFrame context. Option B attempts to apply the assessPerformance() function to each row, but it doesn't reference the row object in any way. Option C tries to apply the assessPerformance() function to the entire DataFrame but does so using an incorrect syntax. Option D correctly applies the assessPerformance() function to each row of the DataFrame using a list comprehension over the result of the collect() method. Option E is similar to D, but it will iterate over rows individually instead of using the collect() method to retrieve all rows at once. While this is still a valid approach, it may be less efficient.
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