A customer wants to store PSM recordings for 100 days and estimates they will have 10 Windows sessions per day for 100 minutes each. What is the minimum storage required for the Vault and PAReplicate for the PSM recordings?
The answer is A
The estimated storage requirement for PSM recordings is approximately 50-250 KB for each minute of a recording session. The recording size is affected by the type of session recording (console vs. GUI recording) as well as by the type and number of activities that are performed during the session.
In this case, the customer wants to store PSM recordings for 100 days and estimates they will have 10 Windows sessions per day for 100 minutes each. This means that the total number of minutes of recording will be 100 days * 10 sessions/day * 100 minutes/session = 100,000 minutes.
At the high end of the estimated storage requirement, this would require 100,000 minutes * 250 KB/minute = 25 GB of storage.
However, the customer may be able to get away with less storage if they use a lower quality recording setting or if they only record certain types of sessions.
After exausting calculation, the best answer is the B.
First of all, we need to understand the minimum quality possible it is 100 KB/s
100 x 10 x 100 x 100 KB + 20 GB.
after we need to convert the value of session KB to GB:
100x10x100x0,0001+20 GB= 30 GB
Another trick question, based on the formula provided by CyberArk: 100(retention) x 10(# of sessions) x 100(minutes each) x 250 (kb/min) + 20GB = 45GB therefore the next smallest size is 250GB so I'd be inclined to agree that the answer is in fact B.
https://docs.cyberark.com/PAS/13.2/en/Content/PAS%20INST/Considerations-Before-Installing-PSM.htm?tocpath=Installation%7CInstall%20PAM%20-%20Self-Hosted%7CInstall%20PSM%7C_____1#:~:text=of%20your%20implementation.-,Planning%20capacity,-Determine%20the%20amount
In the question , we'reasked to identify the size for PSM Rercordings and PARecplicate. if you have a Primary and DR vault , you need to store two copies of the recordings ( one in each Vault ) so you have to double the storage
120GB*2 =240 GB
the correct calculation:
it's (๐_๐๐๐ )=(๐ถ_๐ ๐๐ ๐ ๐๐๐ )(๐ก_๐ ๐๐ ๐ ๐๐๐ )(๐ _(๐ ๐๐ ๐ ๐๐๐ ๐๐๐๐๐๐๐๐๐) )+20๐บ๐ต
so is 25 gb + 20gb = 45 gb. So minimum is 250 GB
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