Exam N10-008 topic 1 question 334 discussion

it's 310 in total, but they asking for "capacity to double the number of clients in the future", so will be 620 - have to be B

Total users = 50 + 35 + 20 + 75 + 130 = 310 users To allow for future doubling, we need a subnet that can accommodate at least 620 users. B. 10.0.0.0/22: This subnet provides 1,024 addresses,

260 max IP's is borrowing on any VLAN, is 9 bits (512 hosts - 2) from 32. = 23 bits for subnet

/23 = 2 subnets of 512 = 1024 IP Addresses to divide up in a virtual environment which can fit the 310 to 620 potential clients.

CIDR Subnets IPs /22 4 1024 /23 2 512 /24 1 256

Number of VLANs: 5 Number of Clients per VLAN: 16, 32, 64, 128, 256 (doubled capacity) Total Number of Clients: 16 + 32 + 64 + 128 + 256 = 496 (doubled capacity) To find the smallest subnet that can accommodate at least 496 clients, we need to find the smallest subnet size (prefix length) that covers this number. A /23 subnet provides 512 IP addresses, which is sufficient for the current requirement of 496 clients and allows room for doubling in the future. So, the answer is a /23 subnet. A /23 subnet has a subnet mask of 255.255.254.0. Keep in mind that using a /23 subnet for this scenario allows for efficient utilization of IP addresses and scalability for future growth. Answer is C

First of all is this about doubling the capacity in each vlan or the total?

I wonder how they came up with the 10.0.0.0/23??? Maybe the question should have been: Which of the following is the SMALLEST subnet capable of this setup? Are we missing something?

The required number of IP addresses for the current VLAN setup is: 50 (vlan 10) + 35 (vlan 20) + 20 (vlan 30) + 75 (vlan 40) + 130 (vlan 50) = 310 To double the capacity in the future, the subnet should have at least 620 IP addresses. The SMALLEST subnet that can accommodate the required VLANs and allow for future growth is: B. 10.0.0.0/22

Why not B? VLAN 10 - 64 /26 VLAN 20 - 64 /26 VLAN 30 - 32 /27 VLAN 40 - 128 /25 VLAN 50 - 256 /24 Total 544 x 2 = 1088 CIDR 21 provides 2,048 Hosts that will cover 1088 Host CIDR 22 will cover 1024 hosts only.

I agree with sandy5040. Absolutely correct explanation.

I thought the answer is A. Explanation: If Vlan10 needed 50 users that means the actual user comes under 64 users (64-2=62 users) and so on Vlan20 = 64, vlan30 = 32, vlan40 = 128, vlan50 = 256 total of 544 users with an extra user in each VLAN.. and in question, we need to double it so it would be 1088 which leads to answering /21. please correct me if I am wrong...

Its "B" for sure, total users is 310 and they want room to double to 620. a /23 only give you 512 address, you need a /22 which gives 1024 addresses.